Što od navedenoga vrijedi za argumente φ1\varphi_1$\varphi_1$ i φ2\varphi_2$\varphi_2$ za svaka dva kompleksna broja z1=r1(cos⁡φ1+isin⁡φ1)z_{1}=r_{1}(\cos \varphi_{1}+i \sin \varphi_{1})$z_{1}=r_{1}(\cos \varphi_{1}+i \sin \varphi_{1})$ i z2=r2(cos⁡φ2+isin⁡φ2)z_{2}=r_{2}(\cos \varphi_{2}+i \sin \varphi_{2})$z_{2}=r_{2}(\cos \varphi_{2}+i \sin \varphi_{2})$ za koje vrijedi z2=−z1z_{2}=-z_{1}$z_{2}=-z_{1}$?

A
∣φ1−φ2∣=π2|\varphi_{1}-\varphi_{2}|=\frac{\pi}{2}$|\varphi_{1}-\varphi_{2}|=\frac{\pi}{2}$
B
∣φ1+φ2∣=π2|\varphi_{1}+\varphi_{2}|=\frac{\pi}{2}$|\varphi_{1}+\varphi_{2}|=\frac{\pi}{2}$
C
∣φ1−φ2∣=π|\varphi_{1}-\varphi_{2}|=\pi$|\varphi_{1}-\varphi_{2}|=\pi$
D
∣φ1+φ2∣=π|\varphi_{1}+\varphi_{2}|=\pi$|\varphi_{1}+\varphi_{2}|=\pi$

Rješenje

Rješenje je skriveno. Klikni gumb iznad za prikaz.