Zadani su $a=\frac{1}{4}x^{3}y^{-1}$$a=\frac{1}{4}x^{3}y^{-1}$ i $b=4x^{-1}y^{3}$$b=4x^{-1}y^{3}$.

Množimo koeficijente i potencije s istim bazama:\n(\frac{1}{4} x^3 y^{-1}) \cdot (4 x^{-1} y^3) = (\frac{1}{4} \cdot 4) \cdot (x^{3-1}) \cdot (y^{-1+3}) = 1 \cdot x^2 \cdot y^2 = x^2 y^2$.

Potenciramo svaki faktor unutar zagrade:\n(\frac{1}{4} x^3 y^{-1})^{-2} = (\frac{1}{4})^{-2} \cdot x^{3 \cdot (-2)} \cdot y^{(-1) \cdot (-2)}.\nIzračunavamo: $16 \cdot x^{-6} \cdot y^2 = 16x^{-6}y^2$$16 \cdot x^{-6} \cdot y^2 = 16x^{-6}y^2$.